3420.31 – The Trapezoid and the Triangle


Find the ratio of the area of the triangle RVW\triangle RVW to the area of the trapezoid STVWSTVW, where VWVW is parallel to TSTS.

Tags:

Solution

The triangles RVW\triangle RVW and RTS\triangle RTS are similar, therefore the bases are in the ratio 511\dfrac{5}{11}. The bases themselves will be, say, 5k5k and 11k11k respectively, where kk is a constant.

The heights of the two triangles are in the same ratio, say, 5m5m and 11m11m. Therefore the ratio of the areas (area=base×height÷2)\text{area} = \text{base} \times \text{height} \div 2) of the triangles is

5k×5h2 11k×11h2 =25121\dfrac{\dfrac{5k \times 5h}{2}}{\ \dfrac{11k \times11h}{2}\ } = \dfrac{25}{121}

Now if the area of RVW\triangle RVW is 25z25z, then the area of the trapezoid STVWSTVW is 121z25z=96z121z - 25z = 96z and the ratio of these areas is,

25z96z=2596\dfrac{25z}{96z} = \dfrac{25}{96}