3420.31 – The Trapezoid and the Triangle


Find the ratio of the area of the triangle RVW\triangle RVW to the area of the trapezoid STVWSTVW, where VWVW is parallel to TSTS.


Solution

The triangles RVW\triangle RVW and RTS\triangle RTS are similar, therefore the bases are in the ratio 511\dfrac{5}{11}. The bases themselves will be, say, 5k5k and 11k11k respectively, where kk is a constant.

The heights of the two triangles are in the same ratio, say, 5m5m and 11m11m. Therefore the ratio of the areas (area=base×height÷2)\text{area} = \text{base} \times \text{height} \div 2) of the triangles is

5k×5h2 11k×11h2 =25121\dfrac{\dfrac{5k \times 5h}{2}}{\ \dfrac{11k \times11h}{2}\ } = \dfrac{25}{121}

Now if the area of RVW\triangle RVW is 25z25z, then the area of the trapezoid STVWSTVW is 121z25z=96z121z - 25z = 96z and the ratio of these areas is,

25z96z=2596\dfrac{25z}{96z} = \dfrac{25}{96}