2530.31 – Mystery Linear Operation


Suppose that the operation \oplus is defined so that the following is true:

5=118=1712=25\begin{aligned}\oplus 5 &= 11 \\\oplus 8 &= 17 \\\oplus 12 &= 25\end{aligned}

With this information, find nn if n=35\oplus n = 35.


Solution

Note that to get from five to eleven add six. To get from eight to seventeen, add nine. To get from twelve to twenty-five, add thirteen. In each case, the number is added to itself plus one:

5=11=5+5+1=2×5+18=17=8+8+1=2×8+112=25=12+12+1=2×12+1\begin{aligned}\oplus 5 &= 11 &&= 5 + 5 + 1 &&= 2 \times 5 + 1 \\\oplus 8 &= 17 &&= 8 + 8 + 1 &&= 2 \times 8 + 1 \\\oplus 12 &= 25 &&= 12 + 12 + 1 &&= 2 \times 12 + 1\end{aligned}

Noticing this pattern, we fill in the missing information and find that if 35=n=2n+135 = \oplus n = 2 n + 1, then 2n=342n = 34 and n=17n = 17.