If 4→3,10→64 \rightarrow 3, 10 \rightarrow 64→3,10→6, and 7→4.57 \rightarrow 4.57→4.5, then what is the formula for x→ ?x \rightarrow \ ?x→ ? Tags: Problem Set 3,Algebra I,Symbol-Pushing Solution 4→3=4+224 \rightarrow 3=\dfrac{4+2}{2}4→3=24+210→6=10+2210 \rightarrow 6=\dfrac{10+2}{2}10→6=210+27→4.5=7+227 \rightarrow 4.5=\dfrac{7+2}{2}7→4.5=27+2x→x+22=x2+1x \rightarrow \dfrac{x+2}{2} = \dfrac{x}{2}+1x→2x+2=2x+1