2510.11 – Defined Operation no. 1


Define an operation DD for positive real numbers so that aDb=ab(a+b)a D b = \dfrac{ab}{(a + b)}.

Then 4D(4D4)4 D (4 D 4) = what?


Solution

In evaluating 4D(4D4)4 D (4 D 4), we start inside the parentheses, as usual.

So 4D(4D4)=4D168=4D2=86=434 D (4 D 4) = 4 D \dfrac{16}{8} = 4 D 2 = \dfrac{8}{6} = \dfrac{4}{3}.