2440.93 – Train Speed


The train roars through the station. A waiting passenger times its transit past the point where she stands. It takes 55 seconds. To pass the whole station requires 1919 seconds from the time the engine enters the station until the time the last car exits it. (The passenger didn't know this, but we do.) The platform is 280280 meters long.

How long is the train and what is its speed?


Solution

In the figure below, PP is the location of the passenger; SS and EE are the start and end (respectively) of the station platform.

Now, it took 1919 seconds from the moment when the front of the train reached SS to the moment when the rear of the train passed EE. We also know that it took 55 seconds from the moment when the front of the train passed PP to the moment when the rear of the train passed PP. Naturally that 55 seconds applies to any other point on the platform, say SS.

So it took 14=19514 = 19-5 seconds for the back of the train to travel the 280280 meters of the platform. Ha! The speed of the train is 28014=20\dfrac{280}{14} = 20 meters per second. If it takes 55 seconds for the whole train to pass a point while going 2020 meters per second, then the train is 100100 m long.

If you convert this speed to kilometers or miles per hour, you'll see that it's not a particularly fast train. But it still roared.