Which of the following inequalities is or are satisfied for all real numbers a,b,c,x,y,z that satisfy the conditions x<a, y<b, and z<c?
I. xy+yz+zx<ab+bc+ca
II. x2+y2+z2<a+b+c
III. xyz<abc
None is satisfied
I only
II only
III only
All are satisfied.
Solution
We search vigorously for counterexamples in which x<a, y<b, and z<c.
I. xy+yz+zx<ab+bc+ca. Let x=y=z=−1 and a=b=c=0, and I is done, i.e., this inequality is false.
II. x2+y2+z2<a+b+c. The same numbers disprove this one.
III. xyz<abc. Let x=y=−1 and z=1, and a=b=0 and c=2. That obliterates III.
So the answer is (a): None of the inequalities is satisfied.